If radius of the $^{27}_{13}Al$ nucleus is taken to be $R_{Al}$, then the radius of $^{125}_{53}Te$ nucleus is nearly

  • [AIPMT 2015]
  • [AIPMT 1990]
  • A

    ${\left( {\frac{{53}}{{13}}} \right)^{\frac{1}{3}}}{R_{Al}}$

  • B

    $\frac{5}{3}{R_{Al}}$

  • C

    $\;\frac{3}{5}{R_{Al}}$

  • D

    $\;{\left( {\frac{{13}}{{53}}} \right)^{\frac{1}{3}}}{R_{Al}}$

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  • [AIIMS 1997]

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